Printing numbers with a delay using asyncio coroutines in Python

Last update on December 21 2024 07:18:38 (UTC/GMT +8 hours)

Write a Python program that creates an asyncio event loop and runs a coroutine that prints numbers from 1 to 7 with a delay of 1 second each.

Sample Solution:

Code:

import asyncio
async def display_numbers():
    for i in range(1, 8):
        print(i)
        await asyncio.sleep(1)
# Run the coroutine using asyncio.run()
asyncio.run(display_numbers())

Output:

1
2
3
4
5
6
7

Explanation:

In the above exercise-

The "display_numbers()" function is an asynchronous coroutine. It uses the 'await' keyword to introduce a pause using await asyncio.sleep(1) after printing each number. This 'sleep()' function introduces a 1 second delay.

The asyncio.run() function runs the “display_numbers()” coroutine. This function is introduced in Python 3.7 and provides a simple and clean way to run an asynchronous function in an event loop.

• Inside the event loop created by asyncio.run(), the display_numbers() coroutine is executed.
• For each iteration of the loop (from 1 to 7), the current number is displayed, and then the coroutine is paused for 1 second using await asyncio.sleep(1).

Flowchart:

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