Python: Sum of all items of a given array of integers where each integer is multiplied by its index

Last update on December 21 2024 07:18:44 (UTC/GMT +8 hours)

Sum of Items Weighted by Index

Write a Python program to compute the sum of all items in a given array of integers where each integer is multiplied by its index. Return 0 if there is no number.

Sample Solution:

Python Code:

# Define a function named sum_index_multiplier that takes a list of numbers (nums) as an argument.
def sum_index_multiplier(nums):
    # Use a generator expression within the sum function to calculate the sum of each element multiplied by its index.
    # The expression j*i for i, j in enumerate(nums) iterates over the elements and their indices.
    return sum(j * i for i, j in enumerate(nums))

# Test the function with different lists of numbers and print the results.

# Test case 1
print(sum_index_multiplier([1,2,3,4]))

# Test case 2
print(sum_index_multiplier([-1,-2,-3,-4]))

# Test case 3
print(sum_index_multiplier([]))

Sample Output:

20
-20
0

Explanation:

Here is a breakdown of the above Python code:

• Function definition:
• The code defines a function named "sum_index_multiplier()" that takes a list of numbers (nums) as an argument.
• Generator Expression and Enumerate:
• The function uses a generator expression within the "sum()" function to calculate the sum of each element multiplied by its index. The expression j * i for i, j in enumerate(nums) iterates over the elements and their indices.
• Return Statement:
• The function returns the result of the sum operation.

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