Python: Find the indices of all occurrences of a given item in a given list

Last update on December 21 2024 07:18:49 (UTC/GMT +8 hours)

Find Indices of Item

Write a Python program to find the indices of all occurrences of a given item in a given list.

Sample Solution-1:

Python Code:

# Define a function named indices_in_list that returns a list of indices where a given item (n) occurs in a list (nums_list).
def indices_in_list(nums_list, n):
    # Use list comprehension to create a list of indices where the item equals n.
    return [idx for idx, i in enumerate(nums_list) if i == n]

# Test the function with different lists and items, and print the results.

# Test case 1
nums = [1,2,3,4,5,2]
print("Original list of numbers:", nums)
n = 2
print("Given Number:", n)
print("Indices of all occurrences of the said item in the given list:")
print(indices_in_list(nums, n))

# Test case 2
nums = [3,1,2,3,4,5,6,3,3]
print("\nOriginal list of numbers:", nums)
n = 3
print("Given Number:", n)
print("Indices of all occurrences of the said item in the given list:")
print(indices_in_list(nums, n))

# Test case 3
nums = [1,2,3,-4,5,2,-4]
print("\nOriginal list of numbers:", nums)
n = -4
print("Given Number:", n)
print("Indices of all occurrences of the said item in the given list:")
print(indices_in_list(nums, n))

# Test case 4
nums = [1,2,3,4,5,2]
print("\nOriginal list of numbers:", nums)
n = 7
print("Given Number:", n)
print("Indices of all occurrences of the said item in the given list:")
print(indices_in_list(nums, n))

Sample Output:

Original list of numbers: [1, 2, 3, 4, 5, 2]
Given Number 2
Indices of all occurrences of the said item in the given list:
[1, 5]

Original list of numbers: [3, 1, 2, 3, 4, 5, 6, 3, 3]
Given Number 3
Indices of all occurrences of the said item in the given list:
[0, 3, 7, 8]

Original list of numbers: [1, 2, 3, -4, 5, 2, -4]
Given Number -4
Indices of all occurrences of the said item in the given list:
[3, 6]

Original list of numbers: [1, 2, 3, 4, 5, 2]
Given Number 7
Indices of all occurrences of the said item in the given list:
[]

Explanation:

Here is a breakdown of the above Python code:

• Function definition:
• The code defines a function named "indices_in_list()" that returns a list of indices where a given item (n) occurs in a list (nums_list).
• List comprehension:
• The function uses list comprehension to iterate through the elements of 'nums_list' along with their indices and creates a list of indices where the element is equal to 'n'.
• Test cases:
• The function is tested with different lists and items using print(indices_in_list(...)).

Visual Presentation:

Flowchart:

Sample Solution-2:

Python Code:

# Import the count function from the itertools module
from itertools import count

# Define a function named indices_in_list that returns a list of indices where a given item (n) occurs in a list (nums_list).
def indices_in_list(nums_list, n):
    # Use list comprehension to create a list of indices where the item equals n, using the count() function to generate indices.
    return [(i) for i, j in zip(count(), nums_list) if j == n]

# Test the function with different lists and items, and print the results.

# Test case 1
nums = [1,2,3,4,5,2]
print("Original list of numbers:", nums)
n = 2
print("Given Number:", n)
print("Indices of all occurrences of the said item in the given list:")
print(indices_in_list(nums, n))

# Test case 2
nums = [3,1,2,3,4,5,6,3,3]
print("\nOriginal list of numbers:", nums)
n = 3
print("Given Number:", n)
print("Indices of all occurrences of the said item in the given list:")
print(indices_in_list(nums, n))

# Test case 3
nums = [1,2,3,-4,5,2,-4]
print("\nOriginal list of numbers:", nums)
n = -4
print("Given Number:", n)
print("Indices of all occurrences of the said item in the given list:")
print(indices_in_list(nums, n))

# Test case 4
nums = [1,2,3,4,5,2]
print("\nOriginal list of numbers:", nums)
n = 7
print("Given Number:", n)
print("Indices of all occurrences of the said item in the given list:")
print(indices_in_list(nums, n))

Sample Output:

Original list of numbers: [1, 2, 3, 4, 5, 2]
Given Number 2
Indices of all occurrences of the said item in the given list:
[1, 5]

Original list of numbers: [3, 1, 2, 3, 4, 5, 6, 3, 3]
Given Number 3
Indices of all occurrences of the said item in the given list:
[0, 3, 7, 8]

Original list of numbers: [1, 2, 3, -4, 5, 2, -4]
Given Number -4
Indices of all occurrences of the said item in the given list:
[3, 6]

Original list of numbers: [1, 2, 3, 4, 5, 2]
Given Number 7
Indices of all occurrences of the said item in the given list:
[]

Explanation:

Here is a breakdown of the above Python code:

• Import statement:
• The code imports the count function from the itertools module.
• Function definition:
• The code defines a function named indices_in_list that returns a list of indices where a given item (n) occurs in a list (nums_list).
• List comprehension with count():
• The function uses list comprehension to iterate through the elements of nums_list along with their indices generated by count(), and creates a list of indices where the element is equal to n.
• Test cases:
• The function is tested with different lists and items using print(indices_in_list(...)).

Flowchart:

Sample Solution-3:

Python Code:

# Import the locate function from the more_itertools module
from more_itertools import locate

# Define a function named indices_in_list that returns a list of indices where a given item (n) occurs in a list (nums_list).
def indices_in_list(nums_list, n):
    # Use the locate function to find all indices where the item equals n and convert it to a list.
    return list(locate(nums_list, lambda x: x == n))

# Test the function with different lists and items, and print the results.

# Test case 1
nums = [1,2,3,4,5,2]
print("Original list of numbers:", nums)
n = 2
print("Given Number:", n)
print("Indices of all occurrences of the said item in the given list:")
print(indices_in_list(nums, n))

# Test case 2
nums = [3,1,2,3,4,5,6,3,3]
print("\nOriginal list of numbers:", nums)
n = 3
print("Given Number:", n)
print("Indices of all occurrences of the said item in the given list:")
print(indices_in_list(nums, n))

# Test case 3
nums = [1,2,3,-4,5,2,-4]
print("\nOriginal list of numbers:", nums)
n = -4
print("Given Number:", n)
print("Indices of all occurrences of the said item in the given list:")
print(indices_in_list(nums, n))

# Test case 4
nums = [1,2,3,4,5,2]
print("\nOriginal list of numbers:", nums)
n = 7
print("Given Number:", n)
print("Indices of all occurrences of the said item in the given list:")
print(indices_in_list(nums, n))

Sample Output:

Original list of numbers: [1, 2, 3, 4, 5, 2]
Given Number 2
Indices of all occurrences of the said item in the given list:
[1, 5]
Original list of numbers: [3, 1, 2, 3, 4, 5, 6, 3, 3]
Given Number 3
Indices of all occurrences of the said item in the given list:
[0, 3, 7, 8]
Original list of numbers: [1, 2, 3, -4, 5, 2, -4]
Given Number -4
Indices of all occurrences of the said item in the given list:
[3, 6]
Original list of numbers: [1, 2, 3, 4, 5, 2]
Given Number 7
Indices of all occurrences of the said item in the given list:
[]

Explanation:

Here is a breakdown of the above Python code:

• Import statement:
• The code imports the "locate" function from the "more_itertools()" module.
• Function definition:
• The code defines a function named "indices_in_list()" that returns a list of indices where a given item (n) occurs in a list (nums_list).
• Use of locate function:
• The "locate()" function is used to find all indices where the element equals n, and the result is converted to a list.
• Test cases:
• The function is tested with different lists and items using print(indices_in_list(...)).

Flowchart:

Python Code Editor:

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