Python: Check whether two given circles are intersecting

Last update on December 21 2024 07:18:50 (UTC/GMT +8 hours)

Circle Intersection Checker

Write a Python program which checks whether two circles in the same plane (with the same center (x,y) and radius) intersect. If intersection occurs, return true, otherwise return false.

Sample Solution:

Python Code:

# Define a function named is_circle_collision that checks if two circles collide.
def is_circle_collision(circle1, circle2):
    # Extract coordinates (x, y) and radius (r) for both circles from the input lists.
    x1, y1, r1 = circle1
    x2, y2, r2 = circle2
    
    # Calculate the distance between the centers of the two circles using the distance formula.
    distance = ((x1 - x2) ** 2 + (y1 - y2) ** 2) ** 0.5
    
    # Check if the distance is less than or equal to the sum of the radii, indicating a collision.
    return distance <= r1 + r2

# Test the function with different circles and print the results.

# Test case 1
print(is_circle_collision([1, 2, 4], [1, 2, 8]))

# Test case 2
print(is_circle_collision([0, 0, 2], [10, 10, 5]))

Sample Output:

True
False

Explanation:

Here is a breakdown of the above Python code:

• Function definition:
• The code defines a function named "is_circle_collision()" that checks if two circles (represented as lists with coordinates [x, y] and radius [r]) collide.
• Circle Parameters Extraction:
• Extracts the coordinates (x, y) and radius (r) for both circles from the input lists.
• Distance calculation:
• Calculates the distance between the centers of the two circles using the distance formula.
• Collision Check:
• Checks if the distance is less than or equal to the sum of the radii, which indicates a collision.
• Test cases:
• The function is tested with different circles, and the results are printed using print(is_circle_collision(...)).

Flowchart:

Python Code Editor:

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