Python: Test if the letters in the second string are present in the first string

Python Basic - 1: Exercise-88 with Solution

Write a Python program that accepts two strings and determines whether the letters in the second string are present in the first string.

Sample Solution:

Python Code:

# Define a function named string_letter_check that takes two strings, str1 and str2, as arguments.
def string_letter_check(str1, str2):
    # Check if all characters in str2 (ignoring case) are present in str1 (ignoring case).
    return all([char in str1.lower() for char in str2.lower()])

# Test the function with different pairs of strings and print the results.
print(string_letter_check("python", "ypth"))    # Expecting True (all characters in str2 are in str1)
print(string_letter_check("python", "ypths"))   # Expecting False (not all characters in str2 are in str1)
print(string_letter_check("python", "ypthon"))  # Expecting True (all characters in str2 are in str1)
print(string_letter_check("123456", "01234"))   # Expecting False (not all characters in str2 are in str1)
print(string_letter_check("123456", "1234"))    # Expecting True (all characters in str2 are in str1)

Sample Output:

True
False
True
False
True

Explanation:

Here is a breakdown of the above Python code:

• Function definition:
• The code defines a function named "string_letter_check()" that takes two strings, 'str1' and 'str2', as arguments.
• Return Statement:
• The function returns 'True' if all characters in 'str2' (ignoring case) are present in 'str1' (ignoring case). Otherwise, it returns 'False'.
• Test cases:
• The function is tested with different pairs of strings using print(string_letter_check(...))

Visual Presentation:

Flowchart:

Python Code Editor:

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