Python: Print subject name and marks in order of its first occurrence

Last update on December 21 2024 07:25:26 (UTC/GMT +8 hours)

Write a Python program that accepts the number of subjects, subject names and marks. Input the number of subjects and then the subject name and marks separated by a space on the next line. Print the subject name and marks in order of appearance.

Sample Solution:

Python Code:

# Import the collections and re modules
import collections, re

# Prompt the user to input the number of subjects
n = int(input("Number of subjects: "))

# Create an ordered dictionary to store subject names and their respective marks
item_order = collections.OrderedDict()

# Loop 'n' times to gather subject names and marks
for i in range(n):
   # Prompt the user to input subject name and marks, split the input into subject_name and item_price
   sub_marks_list = re.split(r'(\d+)$', input("Input Subject name and marks: ").strip())
   subject_name = sub_marks_list[0]
   item_price = int(sub_marks_list[1])
   
   # Check if the subject_name is already in the item_order dictionary
   if subject_name not in item_order:
       # If not, add a new entry with the subject_name as the key and item_price as the value
       item_order[subject_name] = item_price
   else:
       # If it already exists, update the item_order dictionary with the new item_price
       item_order[subject_name] = item_order[subject_name] + item_price

# Iterate over the ordered dictionary and print subject names and their respective marks
for i in item_order:
   print(i + str(item_order[i]))

Sample Output:

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Number of subjects:  3
Input Subject name and marks:  Bengali 58
Input Subject name and marks:  English 62
Input Subject name and marks:  Math 68
Bengali 58
English 62
Math 68 

Flowchart:

Python Code Editor:

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