Python: Read a given CSV file as a dictionary

Last update on December 21 2024 07:25:32 (UTC/GMT +8 hours)

Write a Python program to read a given CSV file as a dictionary.

Sample Solution:

Python Code :

import csv
data = csv.DictReader(open("departments.csv"))
print("CSV file as a dictionary:\n")
for row in data:
   print(row)

departments.csv

department_id, department_name,  manager_id,  location_id
10, Administration, 200, 1700
20, Marketing, 201, 1800
30, Purchasing, 114, 1700
40, Human Resources, 203, 2400
50, Shipping, 121, 1500
60, IT, 103, 1400
70, Public Relations, 204, 2700
80, Sales, 145, 2500

Sample Output:

CSV file as a dictionary:

OrderedDict([('department_id', '10'), (' department_name', ' Administration'), ('  manager_id', ' 200'), ('  location_id', ' 1700')])
OrderedDict([('department_id', '20'), (' department_name', ' Marketing'), ('  manager_id', ' 201'), ('  location_id', ' 1800')])
OrderedDict([('department_id', '30'), (' department_name', ' Purchasing'), ('  manager_id', ' 114'), ('  location_id', ' 1700')])
OrderedDict([('department_id', '40'), (' department_name', ' Human Resources'), ('  manager_id', ' 203'), ('  location_id', ' 2400')])
OrderedDict([('department_id', '50'), (' department_name', ' Shipping'), ('  manager_id', ' 121'), ('  location_id', ' 1500')])
OrderedDict([('department_id', '60'), (' department_name', ' IT'), ('  manager_id', ' 103'), ('  location_id', ' 1400')])
OrderedDict([('department_id', '70'), (' department_name', ' Public Relations'), ('  manager_id', ' 204'), ('  location_id', ' 2700')])
OrderedDict([('department_id', '80'), (' department_name', ' Sales'), ('  manager_id', ' 145'), ('  location_id', ' 2500')])

Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a Python program to read a given CSV file as a list.
Next: Write a Python program to read a given CSV files with initial spaces after a delimiter and remove those initial spaces.