Python Linked List: Access a specific item in a singly linked list using index value

Last update on December 21 2024 07:26:32 (UTC/GMT +8 hours)

Write a Python program to access a specific item in a singly linked list using index value.

Sample Solution:

Python Code:

class Node:
    # Singly linked node
    def __init__(self, data=None):
        self.data = data
        self.next = None
class singly_linked_list:
    def __init__(self):
        # Createe an empty list
        self.tail = None
        self.head = None
        self.count = 0
	
    def append_item(self, data):
        #Append items on the list
        node = Node(data)
        if self.head:
            self.head.next = node
            self.head = node
        else:
            self.tail = node
            self.head = node
        self.count += 1
    
    def __getitem__(self, index):
        if index > self.count - 1:
            return "Index out of range"
        current_val = self.tail
        for n in range(index):
            current_val = current_val.next
        return current_val.data


items = singly_linked_list()
items.append_item('PHP')
items.append_item('Python')
items.append_item('C#')
items.append_item('C++')
items.append_item('Java')

print("Search using index:")
print(items[0])
print(items[1])
print(items[4])
print(items[5])
print(items[10])

Sample Output:

Search using index:
PHP
Python
Java
Index out of range
Index out of range

Flowchart:

Python Code Editor:

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