Python: Find shortest list of values with the keys of a dictionary

Last update on December 21 2024 07:28:35 (UTC/GMT +8 hours)

Write a Python program to find the shortest list of values for the keys in a given dictionary.

Visual Presentation:

Sample Solution:

Python Code:

# Define a function 'test' that takes a dictionary 'dictt' as an argument.
def test(dictt):
    # Define a minimum value for the length of sublists (1 in this case).
    min_value = 1

    # Create a list of keys 'k' for which the length of the associated list 'v' is equal to 'min_value'.
    result = [k for k, v in dictt.items() if len(v) == min_value]

    # Return the list of keys.
    return result

# Create a dictionary 'dictt' where the keys represent grades ('V', 'VI', etc.) and the values are lists of integers.
dictt = {
    'V': [10, 12],
    'VI': [10],
    'VII': [10, 20, 30, 40],
    'VIII': [20],
    'IX': [10, 30, 50, 70],
    'X': [80]
}

# Print a message indicating the start of the code section and display the original dictionary.
print("\nOriginal Dictionary:")
print(dictt)

# Print a message indicating the purpose and generate a list of keys associated with the shortest lists in the 'dictt' dictionary using the 'test' function.
print("\nShortest list of values with the keys of the said dictionary:")
print(test(dictt)) 

Sample Output:

Original Dictionary:
{'V': [10, 12], 'VI': [10], 'VII': [10, 20, 30, 40], 'VIII': [20], 'IX': [10, 30, 50, 70], 'X': [80]}

Shortest list of values with the keys of the said dictionary:
['VI', 'VIII', 'X']

Flowchart:

Python Code Editor:

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