Python leap year checker using Boolean logic

Last update on December 21 2024 07:29:13 (UTC/GMT +8 hours)

Write a Python program that checks whether a given year is a leap year or not using boolean logic.

Sample Solution:

Code:

def check_leap_year(year):
    return (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0)

def main():
    try:
        year = int(input("Input a valid year: "))
        
        if check_leap_year(year):
            print(f"{year} is a leap year.")
        else:
            print(f"{year} is not a leap year.")
    except ValueError:
        print("Invalid input. Please input a valid year.")

if __name__ == "__main__":
    main()

Output:

Input a valid year: 2000
2000 is a leap year.

Input a valid year: 2021
2021 is not a leap year.

In the above exercise the above program prompts the user to input a year and then uses the "is_leap_year()" function to determine if the year is a leap year or not. It prints the appropriate message based on the results.

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