Python Program: Counting and sorting word frequencies

Last update on December 21 2024 07:29:17 (UTC/GMT +8 hours)

Write a Python program that creates a counter of the words in a sentence and prints the words in ascending and descending order of their frequency.

Sample Solution:

Code:

from collections import Counter

def main():
    sentence = "Red Green Black Black Red red Orange Pink Pink Red White."
    
    # Split the sentence into words
    words = sentence.split()
    
    # Create a Counter of the words
    word_counter = Counter(words)
    
    # Print words in ascending order of their frequencies
    print("Words in Ascending Order:")
    sorted_words_asc = sorted(word_counter.items(), key=lambda item: item[1])
    for word, count in sorted_words_asc:
        print(f"{word}: {count}")
    
    print("\n")
    
    # Print words in descending order of their frequencies
    print("Words in Descending Order:")
    sorted_words_desc = sorted(word_counter.items(), key=lambda item: item[1], reverse=True)
    for word, count in sorted_words_desc:
        print(f"{word}: {count}")

if __name__ == "__main__":
    main()

Output:

Words in Ascending Order:
Green: 1
red: 1
Orange: 1
White.: 1
Black: 2
Pink: 2
Red: 3

Words in Descending Order:
Red: 3
Black: 2
Pink: 2
Green: 1
red: 1
Orange: 1
White.: 1

In the exercise above, the words in the sentence are counted using a "Counter" object 'word_counter'. The "sorted()" function sorts words based on their frequencies in both ascending and descending orders. In the "sorted()" function, the 'key' parameter specifies the sorting criteria, and the 'reverse' parameter controls the sorting order. In both ascending and descending order, the program prints the words and their frequencies.

Flowchart:

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