Python counter filter program: Counting and filtering words

Last update on December 21 2024 07:29:19 (UTC/GMT +8 hours)

Write a Python program that creates a 'Counter' for a list of words and removes all items with a count less than a certain value.

Sample Solution:

Code:

from collections import Counter

def main():
    colors = ["Red", "Green", "Black", "Black", "Red", "red", "Orange", "Pink", "Pink", "Red", "White"]
    color_counter = Counter(colors)
    
    min_count = 2
    filtered_counter = {word: count for word, count in color_counter.items() if count >= min_count}
    
    print("Original List:", colors)
    print("Counter:", color_counter)
    print(f"Items with Count >= {min_count}:", filtered_counter)

if __name__ == "__main__":
    main()

Output:

Original List: ['Red', 'Green', 'Black', 'Black', 'Red', 'red', 'Orange', 'Pink', 'Pink', 'Red', 'White']
Counter: Counter({'Red': 3, 'Black': 2, 'Pink': 2, 'Green': 1, 'red': 1, 'Orange': 1, 'White': 1})
Items with Count >= 2: {'Red': 3, 'Black': 2, 'Pink': 2}

In the exercise above, the "Counter" class is used to create a counter for the list of words. The 'filtered_counter' is then created by filtering out items with a count less than the specified 'min_count' from the original counter. Finally results are displayed, including the original list, the counter, and filtered items exceeding or equal to 'min_count'.

Flowchart:

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