Python Generators: Yielding cubes from 1 to n

Last update on December 21 2024 07:30:09 (UTC/GMT +8 hours)

Write a Python program that creates a generator function that yields cubes of numbers from 1 to n. Accept n from the user.

Sample Solution:

Python Code:

def cube_generator(n):
    for i in range(1, n + 1):
        yield i ** 3

# Accept input from the user
n = int(input("Input a number: "))

# Create the generator object
cubes = cube_generator(n)

# Iterate over the generator and print the cubes
print("Cubes of numbers from 1 to", n)
for num in cubes:
    print(num)

Sample Output:

Input a number:  10
Cubes of numbers from 1 to 10
1
8
27
64
125
216
343
512
729
1000

Explanation:

In the above exercise -

• Inside the "cube_generator()" function, a for loop iterates over the range of numbers from 1 to n + 1. For each number i, it calculates the cube by raising i to the power of 3 using the ** operator.
• Instead of using the return statement to return the cube value, it uses the yield keyword. This makes the function a generator, allowing it to generate and yield one cube value at a time when requested.
• The program prompts the user to input a number using the input() function. The input value is then converted to an integer using int() and stored in n.
• The generator object "cubes" is created by calling the cube_generator function with n. This sets up the generator and prepares it for iteration.
• The program then iterates over the "cubes" generator using a for loop. For each iteration, the next cube value is generated and assigned to the variable num.
• The cube values are printed one by one inside the loop using print().

Flowchart:

Python Code Editor:

Contribute your code and comments through Disqus.

Previous: Python Generators Yield Exercise Home.
Next: Python random number generator using generators.