Python: Index of the first element, which is greater than a specified element using itertools module

Last update on December 21 2024 07:31:04 (UTC/GMT +8 hours)

Write a Python program to get the index of the first element that is greater than a specified element using the itertools module.

Sample Solution:

Python Code:

from itertools import takewhile
def first_index(l1, n):
    return len(list(takewhile(lambda x: x[1] <= n, enumerate(l1))))


nums = [12,45,23,67,78,90,100,76,38,62,73,29,83]
print("Original list:")
print(nums)
n = 73
print("\nIndex of the first element which is greater than",n,"in the said list:")
print(first_index(nums,n))
n = 21
print("\nIndex of the first element which is greater than",n,"in the said list:")
print(first_index(nums,n))
n = 80
print("\nIndex of the first element which is greater than",n,"in the said list:")
print(first_index(nums,n))
n = 55
print("\nIndex of the first element which is greater than",n,"in the said list:")
print(first_index(nums,n))

Sample Output:

Original list:
[12, 45, 23, 67, 78, 90, 100, 76, 38, 62, 73, 29, 83]

Index of the first element which is greater than 73 in the said list:
4

Index of the first element which is greater than 21 in the said list:
1

Index of the first element which is greater than 80 in the said list:
5

Index of the first element which is greater than 55 in the said list:
3

Python Code Editor:

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