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Python: Find the list with maximum and minimum length using lambda


Write a Python program to find a list with maximum and minimum length using lambda.

Sample Solution:

Python Code :

# Define a function 'max_length_list' that takes a list of lists 'input_list' as input
def max_length_list(input_list):
    # Calculate the maximum length of the sublists in 'input_list'
    max_length = max(len(x) for x in input_list)
    
    # Find the sublist with the maximum length using the 'max' function and a lambda function
    max_list = max(input_list, key=lambda i: len(i))
    
    # Return a tuple containing the maximum length and the sublist with the maximum length
    return (max_length, max_list)

# Define a function 'min_length_list' that takes a list of lists 'input_list' as input
def min_length_list(input_list):
    # Calculate the minimum length of the sublists in 'input_list'
    min_length = min(len(x) for x in input_list)
    
    # Find the sublist with the minimum length using the 'min' function and a lambda function
    min_list = min(input_list, key=lambda i: len(i))
    
    # Return a tuple containing the minimum length and the sublist with the minimum length
    return (min_length, min_list)

# Create a list of lists named 'list1'
list1 = [[0], [1, 3], [5, 7], [9, 11], [13, 15, 17]]

# Print the original list 'list1'
print("Original list:")
print(list1)

# Print the list with the maximum length of sublists within 'list1'
print("\nList with maximum length of lists:")
print(max_length_list(list1))

# Print the list with the minimum length of sublists within 'list1'
print("\nList with minimum length of lists:")
print(min_length_list(list1))

Sample Output:

Original list:
[[0], [1, 3], [5, 7], [9, 11], [13, 15, 17]]

List with maximum length of lists:
(3, [13, 15, 17])

List with minimum length of lists:
(1, [0])

Python Code Editor:

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