Python: Find the list with maximum and minimum length using lambda
Write a Python program to find a list with maximum and minimum length using lambda.
Sample Solution:
Python Code :
# Define a function 'max_length_list' that takes a list of lists 'input_list' as input
def max_length_list(input_list):
# Calculate the maximum length of the sublists in 'input_list'
max_length = max(len(x) for x in input_list)
# Find the sublist with the maximum length using the 'max' function and a lambda function
max_list = max(input_list, key=lambda i: len(i))
# Return a tuple containing the maximum length and the sublist with the maximum length
return (max_length, max_list)
# Define a function 'min_length_list' that takes a list of lists 'input_list' as input
def min_length_list(input_list):
# Calculate the minimum length of the sublists in 'input_list'
min_length = min(len(x) for x in input_list)
# Find the sublist with the minimum length using the 'min' function and a lambda function
min_list = min(input_list, key=lambda i: len(i))
# Return a tuple containing the minimum length and the sublist with the minimum length
return (min_length, min_list)
# Create a list of lists named 'list1'
list1 = [[0], [1, 3], [5, 7], [9, 11], [13, 15, 17]]
# Print the original list 'list1'
print("Original list:")
print(list1)
# Print the list with the maximum length of sublists within 'list1'
print("\nList with maximum length of lists:")
print(max_length_list(list1))
# Print the list with the minimum length of sublists within 'list1'
print("\nList with minimum length of lists:")
print(min_length_list(list1))
Sample Output:
Original list: [[0], [1, 3], [5, 7], [9, 11], [13, 15, 17]] List with maximum length of lists: (3, [13, 15, 17]) List with minimum length of lists: (1, [0])
Python Code Editor:
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