Python: Sort a list of tuples using Lambda
Write a Python program to sort a list of tuples using Lambda.
Sample Solution:
Python Code :
# Create a list of tuples named 'subject_marks', each tuple containing a subject and its corresponding marks
subject_marks = [('English', 88), ('Science', 90), ('Maths', 97), ('Social sciences', 82)]
# Display the original list of tuples to the console
print("Original list of tuples:")
print(subject_marks)
# Sort the 'subject_marks' list of tuples based on the second element of each tuple (the marks),
# using a lambda function as the sorting key to extract the second element
subject_marks.sort(key=lambda x: x[1])
# Display the sorted list of tuples to the console
print("\nSorting the List of Tuples:")
print(subject_marks)
Sample Output:
Original list of tuples: [('English', 88), ('Science', 90), ('Maths', 97), ('Social sciences', 82)] Sorting the List of Tuples: [('Social sciences', 82), ('English', 88), ('Science', 90), ('Maths', 97)]
Explanation:
In the exercise above -
- subject_marks = [('English', 88), ('Science', 90), ('Maths', 97), ('Social sciences', 82)]: Initializes a list of tuples named 'subject_marks'. Each tuple contains a subject (string) as its first element and the corresponding marks (integer) as its second element.
- print("Original list of tuples:"): Prints a message indicating that the following output will display the original list of tuples.
- print(subject_marks): Displays the original list of tuples ('subject_marks') to the console.
- subject_marks.sort(key=lambda x: x[1]): Sorts the list of tuples (subject_marks) based on the second element of each tuple (i.e., the marks). It uses a lambda function as the sorting key, which extracts the second element (x[1]) for sorting purposes.
- print("\nSorting the List of Tuples:"): Prints a message indicating that the following output will display the sorted list of tuples.
- print(subject_marks): Displays the sorted list of tuples (now sorted based on marks) to the console.
Python Code Editor:
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