Python: Remove all elements from a given list present in another list using lambda

Last update on December 21 2024 07:31:26 (UTC/GMT +8 hours)

Write a Python program to remove all elements from a given list present in another list using lambda.

Sample Solution:

Python Code :

# Define a function 'index_on_inner_list' that removes elements from 'list1' present in 'list2'
def index_on_inner_list(list1, list2):
    # Use the 'filter' function with a lambda to filter elements in 'list1' not present in 'list2'
    result = list(filter(lambda x: x not in list2, list1))
    
    # Return the filtered list
    return result

# Create two lists 'list1' and 'list2' containing integers
list1 = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
list2 = [2, 4, 6, 8]

# Print the original lists 'list1' and 'list2'
print("Original lists:")
print("list1:", list1)
print("list2:", list2)

# Remove elements from 'list1' that are present in 'list2' using 'index_on_inner_list' function
print("\nRemove all elements from 'list1' present in 'list2':")
print(index_on_inner_list(list1, list2)) 

Sample Output:

Original lists:
list1: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
list2: [2, 4, 6, 8]

Remove all elements from 'list1' present in 'list2:
[1, 3, 5, 7, 9, 10]

Python Code Editor:

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