Python: Find all index positions of the maximum and minimum values in a given list using lambda

Last update on December 21 2024 07:31:30 (UTC/GMT +8 hours)

Write a Python program to find the index position and value of the maximum and minimum values in a given list of numbers using lambda.

Sample Solution:

Python Code :

# Define a function 'position_max_min' that finds the positions of the maximum and minimum values in a list
def position_max_min(nums):
    # Find the maximum value and its index in 'nums' using 'max' function with 'enumerate'
    # The 'key' argument specifies a lambda function to evaluate each element by its value
    max_result = max(enumerate(nums), key=(lambda x: x[1]))
    
    # Find the minimum value and its index in 'nums' using 'min' function with 'enumerate'
    # The 'key' argument specifies a lambda function to evaluate each element by its value
    min_result = min(enumerate(nums), key=(lambda x: x[1]))
    
    # Return a tuple containing the index position and value of the maximum and minimum values
    return max_result, min_result

# Create a list 'nums' containing numerical values including integers and floats
nums = [12, 33, 23, 10.11, 67, 89, 45, 66.7, 23, 12, 11, 10.25, 54]

# Print the original list 'nums'
print("Original list:")
print(nums)

# Find the index position and value of the maximum and minimum values using 'position_max_min' function
result = position_max_min(nums)

# Print the index position and value of the maximum and minimum values in the list 'nums'
print("\nIndex position and value of the maximum value of the said list:")
print(result[0])

print("\nIndex position and value of the minimum value of the said list:")
print(result[1]) 

Sample Output:

Original list:
[12, 33, 23, 10.11, 67, 89, 45, 66.7, 23, 12, 11, 10.25, 54]

Index position and value of the maximum value of the said list:
(5, 89)

Index position and value of the minimum value of the said list:
(3, 10.11)

Python Code Editor:

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