Python: Pack consecutive duplicates of a given list elements into sublists

Last update on December 21 2024 13:10:08 (UTC/GMT +8 hours)

Pack Consecutive Duplicates into Sublists

Write a Python program to pack consecutive duplicates of a given list of elements into sublists.

Sample Solution:

Python Code:

# Import the 'groupby' function from the 'itertools' module
from itertools import groupby

# Define a function 'compress' that takes a list of numbers 'l_nums' as input
def compress(l_nums):
    # Use 'groupby' to group consecutive duplicates and return the unique keys
    return [key for key, group in groupby(l_nums)] 

# Define a list 'n_list' with consecutive duplicate elements
n_list = [0, 0, 1, 2, 3, 4, 4, 5, 6, 6, 6, 7, 8, 9, 4, 4]

# Print a message indicating the purpose of the following output
print("Original list:") 

# Print the original list 'n_list'
print(n_list)

# Print a message indicating the purpose of the following output
print("\nAfter removing consecutive duplicates:")

# Call the 'compress' function with 'n_list' as an argument and print the result with consecutive duplicates removed
print(compress(n_list))

Sample Output:

Original list:
[0, 0, 1, 2, 3, 4, 4, 5, 6, 6, 6, 7, 8, 9, 4, 4]

After removing consecutive duplicates:
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 4]

Flowchart:

Python Code Editor:

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