Python: Compute the square of first N Fibonacci numbers, use map function and generate a list of the numbers

Last update on December 21 2024 07:34:07 (UTC/GMT +8 hours)

Write a Python program to compute the square of the first N Fibonacci numbers, using the map function and generate a list of the numbers.

Fibonacci numbers:

From Wikipedia,
In mathematics, the Fibonacci numbers, commonly denoted Fn, form a sequence, called the Fibonacci sequence, such that each number is the sum of the two preceding ones, starting from 0 and 1. That is,

F₀ = 0,   F₁ = 1,

and

F_n = F_{n - 1} + F_{n - 2},

for n > 1.

The beginning of the sequence is thus:

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144,....

Sample Solution:

Python Code :

# Import the 'itertools' module
import itertools

# Set the value of 'n' to 10
n = 10

# Define a generator function named 'fibonacci_nums' to generate Fibonacci numbers
def fibonacci_nums(x=0, y=1):
    yield x
    while True:
        yield y
        x, y = y, x + y

# Print a message indicating the operation to be performed
print("First 10 Fibonacci numbers:")

# Use itertools.islice to obtain the first 10 Fibonacci numbers and store the result in 'result'
result = list(itertools.islice(fibonacci_nums(), n))

# Print the result of the islice operation as a list
print(result)

# Define a lambda function named 'square' to calculate the square of a given number
square = lambda x: x * x 

# Print a message indicating the operation to be performed
print("\nAfter squaring said numbers of the list:")

# Use the map function to apply the 'square' function to each element in 'result'
# and print the result as a list of squared numbers
print(list(map(square, result)))

Sample Output:

First 10 Fibonacci numbers:
[0, 1, 1, 2, 3, 5, 8, 13, 21, 34]

After squaring said numbers of the list:
[0, 1, 1, 4, 9, 25, 64, 169, 441, 1156]

Python Code Editor:

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