Python Math: Find the smallest multiple of the first n numbers

Last update on December 21 2024 07:34:22 (UTC/GMT +8 hours)

Write a Python program to find the smallest multiple of the first n numbers. Also, display the factors.

Sample Solution:

Python Code:

def smallest_multiple(n):
    if (n<=2):
      return n
    i = n * 2
    factors = [number  for number in range(n, 1, -1) if number * 2 > n]
    print(factors)

    while True:
        for a in factors:
            if i % a != 0:
                i += n
                break
            if (a == factors[-1] and i % a == 0):
                return i
                
print(smallest_multiple(13))
print(smallest_multiple(11))
print(smallest_multiple(2))
print(smallest_multiple(1))

Sample Output:

[13, 12, 11, 10, 9, 8, 7]
360360
[11, 10, 9, 8, 7, 6]
27720
2
1

Flowchart:

Python Code Editor:

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