Python Exercises: Check whether a given number is a Disarium number or unhappy number
Write a Python program to check whether a given number is a Disarium number or an unhappy number.
A Disarium number is a number defined by the following process:
Sum of its digits powered with their respective position is equal to the original number.
For example 175 is a Disarium number:
As 11+32+53 = 135
Some other DISARIUM are 89, 175, 518 etc.
Pictorial Presentation:
Sample Solution-1:
Python Code:
def is_disarium(num):
temp = 0
for i in range(len(str(num))):
temp += int(str(num)[i]) ** (i + 1)
return temp == num
num = 25
print("\nIs",num,"is Disarium number?",is_disarium(num))
num = 89
print("\nIs",num,"is Disarium number?",is_disarium(num))
num = 75
print("\nIs",num,"is Disarium number?",is_disarium(num))
num = 125
print("\nIs",num,"is Disarium number?",is_disarium(num))
num = 518
print("\nIs",num,"is Disarium number?",is_disarium(num))
Sample Output:
Is 25 is Disarium number? False Is 89 is Disarium number? True Is 75 is Disarium number? False Is 125 is Disarium number? False Is 518 is Disarium number? True
Flowchart:
Sample Solution-2:
Python Code:
def is_disarium(num):
flag = (num == sum([int(str(num)[i-1])**i for i in range(1,len(str(num))+1)]))
return flag
num = 25
print("\nIs",num,"is Disarium number?",is_disarium(num))
num = 89
print("\nIs",num,"is Disarium number?",is_disarium(num))
num = 75
print("\nIs",num,"is Disarium number?",is_disarium(num))
num = 125
print("\nIs",num,"is Disarium number?",is_disarium(num))
num = 518
print("\nIs",num,"is Disarium number?",is_disarium(num))
Sample Output:
Is 25 is Disarium number? False Is 89 is Disarium number? True Is 75 is Disarium number? False Is 125 is Disarium number? False Is 518 is Disarium number? True
Flowchart:
Python Code Editor:
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Previous Python Exercise: Cap a number within the inclusive range specified by the given boundary values x and y.
Next Python Exercise: Check a number is a repdigit number or not.
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