NumPy: Compute the cross product of two given vectors

NumPy: Linear Algebra Exercise-3 with Solution

Write a NumPy program to compute the cross product of two given vectors.

NumPy: Cross product of two vectors

Sample Solution :

Python Code :

import numpy as np

# Define two 2x2 matrices 'p' and 'q'
p = [[1, 0], [0, 1]]
q = [[1, 2], [3, 4]]

# Display the original matrices 'p' and 'q'
print("Original matrices:")
print(p)
print(q)

# Compute the cross product of matrices 'p' and 'q' using np.cross for both orders p x q and q x p
result1 = np.cross(p, q)
result2 = np.cross(q, p)

# Display the cross product of the matrices for both orders
print("Cross product of the said two vectors (p, q):")
print(result1)
print("Cross product of the said two vectors (q, p):")
print(result2) 

Sample Output:

original matrix:
[[1, 0], [0, 1]]
[[1, 2], [3, 4]]
cross product of the said two vectors(p, q):
[ 2 -3]
cross product of the said two vectors(q, p):
[-2  3]

Explanation:

p = [[1, 0], [0, 1]]

q = [[1, 2], [3, 4]]

At first two 2x2 matrixes p and q have been declared.

result1 = np.cross(p, q) calculates the cross product of p and q.

p = [[1, 0, 0],

[0, 1, 0]]

q = [[1, 2, 0],

[3, 4, 0]]

Now, calculate the cross product:

result1[0] = p[0] x q[0] = (0, 0, 2)

result1[1] = p[1] x q[1] = (0, 0, -2)

Thus, result1 is a 2x3 matrix:

[[ 0, 0, 2],

[ 0, 0, -2]]

result2 = np.cross(q, p) calculates the cross product of q and p (reversing the order of operands):

result2[0] = q[0] x p[0] = (0, 0, -2)

result2[1] = q[1] x p[1] = (0, 0, 2)

Thus, result2 is a 2x3 matrix:

[[ 0, 0, -2],

[ 0, 0, 2]]

Python-Numpy Code Editor:

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