NumPy: Check element-wise True/False of a given array where signbit is set
Write a NumPy program to check element-wise True/False of a given array where signbit is set.
Sample array: [-4, -3, -2, -1, 0, 1, 2, 3, 4]
Sample Solution:
Python Code:
# Importing the NumPy library
import numpy as np
# Creating an array with integer values ranging from -4 to 4
x = np.array([-4, -3, -2, -1, 0, 1, 2, 3, 4])
# Displaying the original array
print("Original array: ")
print(x)
# Calculating sign bit of each element in the array using np.signbit()
r1 = np.signbit(x)
# Comparing if each element is less than zero to determine sign bit as a boolean array
r2 = x < 0
# Verifying if both approaches yield the same result
assert np.array_equiv(r1, r2)
# Displaying the sign bit of each element in the array
print(r1)
Sample Output:
Original array: [-4 -3 -2 -1 0 1 2 3 4] [ True True True True False False False False False]
Explanation:
x = np.array([-4, -3, -2, -1, 0, 1, 2, 3, 4]): This code initializes a NumPy array x with 9 integers ranging from -4 to 4.
r1 = np.signbit(x): Here np.signbit(x) function returns a boolean array with the same shape as x, where True corresponds to a negative value and False corresponds to a non-negative value.
r2 = x < 0: Here the expression x < 0 returns a boolean array with the same shape as x, where True corresponds to a negative value and False corresponds to a non-negative value.
assert np.array_equiv(r1, r2): As the above two results are equivalent therefore assert returns true.
Python-Numpy Code Editor: