Pandas Data Series: Compute difference of differences between consecutive numbers of a given series

Pandas: Data Series Exercise-26 with Solution

Write a Pandas program to compute difference of differences between consecutive numbers of a given series.

Sample Solution :

Python Code :

import pandas as pd
series1 = pd.Series([1, 3, 5, 8, 10, 11, 15])
print("Original Series:")
print(series1)
print("\nDifference of differences between consecutive numbers of the said series:")
print(series1.diff().tolist())
print(series1.diff().diff().tolist())

Sample Output:

Original Series:
0     1
1     3
2     5
3     8
4    10
5    11
6    15
dtype: int64

Difference of differences between consecutive numbers of the said series:
[nan, 2.0, 2.0, 3.0, 2.0, 1.0, 4.0]
[nan, nan, 0.0, 1.0, -1.0, -1.0, 3.0]

Explanation:

In the above exercise -

series1 = pd.Series([1, 3, 5, 8, 10, 11, 15]): This code creates a Pandas Series object 'series1' containing seven integers.

series1.diff().tolist(): This line applies the .diff() method to the Pandas Series object 'series1' to compute the first discrete difference of the Series object. The .tolist() method is used to convert the resulting Pandas Series object into a Python list. The resulting list contains the difference between each pair of adjacent elements in the original Series object 'series1'.

series1.diff().diff().tolist(): This line applies the .diff() method again to the result of the first .diff() method call to compute the second discrete difference of the Series object. The .tolist() method is again used to convert the resulting Pandas Series object into a Python list. The resulting list contains the difference between each pair of adjacent elements in the list obtained in the first line.

Python-Pandas Code Editor:

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