Pandas: Find the index of a given substring of a DataFrame column
Write a Pandas program to find the index of a given substring of a DataFrame column.
Sample Solution:
Python Code :
import pandas as pd
df = pd.DataFrame({
'name_code': ['c001','c002','c022', 'c2002', 'c2222'],
'date_of_birth ': ['12/05/2002','16/02/1999','25/09/1998','12/02/2022','15/09/1997'],
'age': [18.5, 21.2, 22.5, 22, 23]
})
print("Original DataFrame:")
print(df)
print("\nCount occurrence of 22 in date_of_birth column:")
df['Index'] = list(map(lambda x: x.find('22'), df['name_code']))
print(df)
Sample Output:
Original DataFrame: name_code date_of_birth age 0 c001 12/05/2002 18.5 1 c002 16/02/1999 21.2 2 c022 25/09/1998 22.5 3 c2002 12/02/2022 22.0 4 c2222 15/09/1997 23.0 Count occurrence of 22 in date_of_birth column: name_code date_of_birth age Index 0 c001 12/05/2002 18.5 -1 1 c002 16/02/1999 21.2 -1 2 c022 25/09/1998 22.5 2 3 c2002 12/02/2022 22.0 -1 4 c2222 15/09/1997 23.0 1
Python Code Editor:
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