Python: Find the dictionary key whose case is different than all other keys

Python Programming Puzzles: Exercise-62 with Solution

Write a Python program to find the dictionary key whose case is different from all other keys.

Input:
{'red': '', 'GREEN': '', 'blue': 'orange'}
Output:
GREEN

Input:
{'RED': '', 'GREEN': '', 'orange': '#125GD'}
Output:
orange

Visual Presentation:

Sample Solution:

Python Code:

# License: https://bit.ly/3oLErEI

def test(dict_data):
    # Iterate over each key in the dictionary
    for different in dict_data:
        # Check if the case of the current key is different from all other keys
        if all(k.islower() != different.islower() for k in dict_data if k != different):
            # Return the key with a different case
            return different
 
# Example 1
dict_data1 = {"red": "", "GREEN": "", "blue": "orange"}
print("Original dictionary key-values:")
print(dict_data1)
print("Find the dictionary key whose case is different than all other keys:")
print(test(dict_data1))

# Example 2
dict_data2 = {"RED": "", "GREEN": "", "orange": "#125GD"}
print("\nOriginal dictionary key-values:")
print(dict_data2)
print("Find the dictionary key whose case is different than all other keys:")
print(test(dict_data2))

Sample Output:

Original dictionary key-values:
{'red': '', 'GREEN': '', 'blue': 'orange'}
Find the dictionary key whose case is different than all other keys:
GREEN

Original dictionary key-values:
{'RED': '', 'GREEN': '', 'orange': '#125GD'}
Find the dictionary key whose case is different than all other keys:
orange

Flowchart:

Python Code Editor :

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