Python: Create a new string by taking a string, and word by word rearranging its characters in ASCII order

Python Programming Puzzles: Exercise-69 with Solution

Write a Python program to create a new string by taking a string, and word by word rearranging its characters in ASCII order.

Input: Ascii character table
Output:
Aciis aaccehrrt abelt

Input: maltos won
Output:
almost now

Visual Presentation:

Sample Solution-1:

Python Code:

# Define a function named 'test' that takes a string 'strs' as input
def test(strs):
    # Using list comprehension to iterate over words in the input string, sorting the characters of each word in ASCII order
    # Then, joining the sorted words into a new string with spaces between them
    return " ".join("".join(sorted(w)) for w in strs.split(' '))

# Example 1
strs1 = "Ascii character table"
print("Original string:", strs1)
print("New string by said string, and word by word rearranging its characters in ASCII order:")
print(test(strs1))

# Example 2
strs2 = "maltos won"
print("\nOriginal string:", strs2)
print("New string by said string, and word by word rearranging its characters in ASCII order:")
print(test(strs2))

Sample Output:

Original string: Ascii character table
New string by said string, and word by word rearranging its characters in ASCII order:
Aciis aaccehrrt abelt

Original string: maltos won
New string by said string, and word by word rearranging its characters in ASCII order:
almost now

Flowchart:

Sample Solution-2:

Python Code:

# License: https://bit.ly/3oLErEI

# Define a function named 'test' that takes a string 'strs' as input
def test(strs):
    # Split the input string into a list of words
    words = strs.split(' ')
    rwords = []  # Initialize an empty list to store the results
    
    # Iterate over each word in the list of words
    for word in words:
        occurrences = {}  # Initialize an empty dictionary to store character occurrences
        # Count occurrences of each character in the word
        for c in word:
            occurrences[c] = occurrences.get(c, 0) + 1
        
        subsequence = []  # Initialize an empty list to store characters in the subsequence
        # Iterate over the dictionary items and create a subsequence based on character occurrences
        for c, count in occurrences.items():
            subsequence += [c]*count
        
        subsequence.sort()  # Sort the subsequence in ASCII order
        
        # Repeat the subsequence to match the length of the original word
        subsequence = subsequence*(len(word)//len(subsequence)) + subsequence[:len(word)%len(subsequence)]
        
        # Join the characters of the subsequence to form a rearranged word and append it to the result list
        rwords.append(''.join(subsequence))
    
    # Join the rearranged words into a new string with spaces between them
    return ' '.join(rwords)

# Example 1
strs1 = "Ascii character table"
print("Original string:", strs1)
print("New string by said string, and word by word rearranging its characters in ASCII order:")
print(test(strs1))

# Example 2
strs2 = "maltos won"
print("\nOriginal string:", strs2)
print("New string by said string, and word by word rearranging its characters in ASCII order:")
print(test(strs2))

Output:

Original string: Ascii character table
New string by said string, and word by word rearranging its characters in ASCII order:
Aciis aaccehrrt abelt

Original string: maltos won
New string by said string, and word by word rearranging its characters in ASCII order:
almost now

Flowchart:

Python Code Editor :

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