Python: Find the sublist of numbers with only odd digits in increasing order

Last update on December 21 2024 07:44:22 (UTC/GMT +8 hours)

Increasing Odd-Digit Sublist

Write a Python program to find the sublist of numbers from a given list of numbers with only odd digits in increasing order.

Input:
[1, 3, 79, 10, 4, 2, 39]
Output:
[1, 3, 39, 79]

Input:
[11, 31, 40, 68, 77, 93, 48, 1, 57]
Output:
[1, 11, 31, 57, 77, 93]

Input:
[9, -2, 3, 4, -2, 0, 2, -3, 8, -1]
Output:
[-3, -1, 3, 9]

Visual Presentation:

Sample Solution:

Python Code:

# License: https://bit.ly/3oLErEI

# Define a function named 'test' that takes a list of numbers 'nums' as input
def test(nums):
    # Use a list comprehension to filter numbers with only odd digits and sort them in increasing order
    return sorted(n for n in nums if all(int(c) % 2 for c in str(abs(n))))

# Example 1
nums1 = [1, 3, 79, 10, 4, 2, 39]
print("Original list of numbers:")
print(nums1)
print("Sublist of numbers with only odd digits in increasing order:")
print(test(nums1))

# Example 2
nums2 = [11, 31, 40, 68, 77, 93, 48, 1, 57]
print("\nOriginal list of numbers:")
print(nums2)
print("Sublist of numbers with only odd digits in increasing order:")
print(test(nums2))

# Example 3
nums3 = [9, -2, 3, 4, -2, 0, 2, -3, 8, -1]
print("\nOriginal list of numbers:")
print(nums3)
print("Sublist of numbers with only odd digits in increasing order:")
print(test(nums3))

Sample Output:

Original list of numbers:
[1, 3, 79, 10, 4, 2, 39]
Sublist of numbers of the said list with only odd digits in increasing order:
[1, 3, 39, 79]

Original list of numbers:
[11, 31, 40, 68, 77, 93, 48, 1, 57]
Sublist of numbers of the said list with only odd digits in increasing order:
[1, 11, 31, 57, 77, 93]

Original list of numbers:
[9, -2, 3, 4, -2, 0, 2, -3, 8, -1]
Sublist of numbers of the said list with only odd digits in increasing order:
[-3, -1, 3, 9]

Flowchart:

Python Code Editor :

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