Python: Find an increasing sequence consisting of the elements of the original list

Last update on December 21 2024 07:44:23 (UTC/GMT +8 hours)

Increasing Sequence from List

Write a Python program to find an increasing sequence consisting of the elements of the original list.

Input:
[1, 3, 79, 10, 4, 2, 39]
Output:
[1, 2, 3, 4, 10, 39, 79]

Input: 
[11, 31, 40, 68, 77, 93, 48, 1, 57]
Output:
[1, 11, 31, 40, 48, 57, 68, 77, 93]

Input: 
[9, -2, 3, 4, -2, 0, 2, -3, 8, -1]
Output:
[-3, -2, -1, 0, 2, 3, 4, 8, 9]

Visual Presentation:

Sample Solution:

Python Code:

# License: https://bit.ly/3oLErEI

# Define a function named 'test' that takes a list of numbers 'nums' as input
def test(nums):
    # Use the 'set' data structure to remove duplicates and then sort the unique elements
    result = sorted(set(nums))
    # Return the sorted and unique elements as the result
    return result
  
# Example 1
nums1 = [1, 3, 79, 10, 4, 2, 39]
print("Original list of numbers:")
print(nums1)
print("Increasing sequence consisting of the elements of the said list:")
print(test(nums1))

# Example 2
nums2 = [11, 31, 40, 68, 77, 93, 48, 1, 57]
print("\nOriginal list of numbers:")
print(nums2)
print("Increasing sequence consisting of the elements of the said list:")
print(test(nums2))

# Example 3
nums3 = [9, -2, 3, 4, -2, 0, 2, -3, 8, -1]
print("\nOriginal list of numbers:")
print(nums3)
print("Increasing sequence consisting of the elements of the said list:")
print(test(nums3))

Sample Output:

Original list of numbers:
[1, 3, 79, 10, 4, 2, 39]
Increasing sequence consisting of the elements of the said list:
[1, 2, 3, 4, 10, 39, 79]

Original list of numbers:
[11, 31, 40, 68, 77, 93, 48, 1, 57]
Increasing sequence consisting of the elements of the said list:
[1, 11, 31, 40, 48, 57, 68, 77, 93]

Original list of numbers:
[9, -2, 3, 4, -2, 0, 2, -3, 8, -1]
Increasing sequence consisting of the elements of the said list:
[-3, -2, -1, 0, 2, 3, 4, 8, 9]

Flowchart:

Python Code Editor :

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