Python: Find the vowels from each of the original texts (y counts as a vowel at the end of the word)

Last update on December 21 2024 07:44:24 (UTC/GMT +8 hours)

Extract Vowels with Y as Vowel

Write a Python program to find the vowels from each of the original texts (y counts as a vowel at the end of the word) from a given list of strings.

Input:  
['w3resource', 'Python', 'Java', 'C++']
Output:
['eoue', 'o', 'aa', '']

Input:  
['ably', 'abruptly', 'abecedary', 'apparently', 'acknowledgedly']
Output:
['ay', 'auy', 'aeeay', 'aaey', 'aoeey']

Visual Presentation:

Sample Solution:

Python Code:

# License: https://bit.ly/3oLErEI

# Define a function named 'test' that takes a list of strings 'strs' as input
def test(strs):
    # Use a list comprehension to iterate over each text in 'strs'
    return [
        "".join(c for c in text if c.lower() in "aeiou") + (text[-1] if text[-1].lower() == "y" else "")
        for text in strs
    ]

# Example 1
strs1 = ["w3resource", "Python", "Java", "C++"]
print("Original List of strings:", strs1)
print("Vowels from each of the original texts (y counts as a vowel at the end of the word:")
print(test(strs1))

# Example 2
strs2 = ["ably", "abruptly", "abecedary", "apparently", "acknowledgedly"]
print("\nOriginal List of strings:", strs2)
print("Positions of all uppercase vowels (not counting Y) in even indices:")
print(test(strs2))

Sample Output:

Original List of strings: ['w3resource', 'Python', 'Java', 'C++']
Vowels from each of the original texts (y counts as a vowel at the end of the word:
['eoue', 'o', 'aa', '']

Original List of strings: ['ably', 'abruptly', 'abecedary', 'apparently', 'acknowledgedly']
Positions of all uppercase vowels (not counting Y) in even indices:
['ay', 'auy', 'aeeay', 'aaey', 'aoeey']

Flowchart:

Python Code Editor :

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Find an increasing sequence consisting of the elements of the original list.
Next: Find a valid substring of s that contains matching brackets, at least one of which is nested.