Python: Find an integer with the given number of even and odd digits

Last update on December 21 2024 07:44:24 (UTC/GMT +8 hours)

Integer with Specified Even and Odd Digits

Write a Python program to find an integer (n >= 0) with the given number of even and odd digits.

Input: 
Number of even digits: 2 ,Number of odd digits: 3
Output:
22333

Input: 
Number of even digits: 4 ,Number of odd digits: 7
Output:
22223333333

Sample Solution:

Python Code:

# License: https://bit.ly/3oLErEI

# Define a function named 'test' that takes two parameters 'evens' and 'odds'
def test(evens, odds):    
    # Generate an integer (>= 0) with the given number of even and odd digits
    return int(evens * "2" + odds * "3")   

# Example 1
evens1 = 2
odds1 = 3
print("Number of even digits:", evens1, ", Number of odd digits:", odds1)
print("Integer (>= 0) with the given number of even and odd digits:")
print(test(evens1, odds1))

# Example 2
evens2 = 4
odds2 = 7
print("\nNumber of even digits:", evens2, ", Number of odd digits:", odds2)
print("Integer (>= 0) with the given number of even and odd digits:")
print(test(evens2, odds2))

Sample Output:

Number of even digits: 2 ,Number of odd digits: 3
Integer(>= 0) with the given number of even and odd digits:
22333

Number of even digits: 4 ,Number of odd digits: 7
Integer(>= 0) with the given number of even and odd digits:
22223333333

Flowchart:

Python Code Editor :

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