Python: Get the difference between a given number and 17, if the number is greater than 17 return double the absolute difference
Difference from 17
Write a Python program to calculate the difference between a given number and 17. If the number is greater than 17, return twice the absolute difference.
Python if-else syntax:
if condition : indentedStatementBlockForTrueCondition else: indentedStatementBlockForFalseCondition
These statement blocks can have any number of statements, and can include about any kind of statement.
Pictorial Presentation:
Sample Solution:
Python Code:
# Define a function named "difference" that takes an integer parameter "n"
def difference(n):
# Check if n is less than or equal to 17
if n <= 17:
# If n is less than or equal to 17, return the absolute difference between 17 and n
return 17 - n
else:
# If n is greater than 17, return the absolute difference between n and 17 multiplied by 2
return (n - 17) * 2
# Call the "difference" function with the argument 22 and print the result
print(difference(22))
# Call the "difference" function with the argument 14 and print the result
print(difference(14))
Sample Output:
10 3
Explanation:
The said script defines a function called 'difference' that takes input(n) as an argument. Using an if-else statement the function checks whether the input value of n is less than or equal to 17. If the input value of n is less than or equal to 17, the function will return the difference of 17 - n. If the input value of n is greater than 17, the function will return double the difference of n - 17.
Now the script calls the function twice with the input values of 22 and 14, respectively.
In the first case the input is greater than 17, so the function returns (22-17)*2 = 10. Therefore, the script will print 10.
In the second case the input value is less than or equal to 17, so the function returns 17-14 = 3. Therefore, the script will print 3.
Flowchart:
Python Code Editor:
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