Python Exercise: Find numbers between two numbers where each digit of a number is an even number

Last update on December 21 2024 07:23:16 (UTC/GMT +8 hours)

Write a Python program to find numbers between 100 and 400 (both included) where each digit of a number is an even number. The numbers obtained should be printed in a comma-separated sequence.

Pictorial Presentation:

Sample Solution:

Python Code:

# Create an empty list named 'items'
items = []

# Iterate through numbers from 100 to 400 (inclusive) using the range function
for i in range(100, 401):
    # Convert the current number 'i' to a string and store it in the variable 's'
    s = str(i)
    
    # Check if each digit in the current number 'i' is even (divisible by 2)
    if (int(s[0]) % 2 == 0) and (int(s[1]) % 2 == 0) and (int(s[2]) % 2 == 0):
        # If all digits are even, append the string representation of 'i' to the 'items' list
        items.append(s)

# Join the elements in the 'items' list separated by ',' and print the result
print(",".join(items)) 

Sample Output:

200,202,204,206,208,220,222,224,226,228,240,242,244,246,248,260,262,264,266,268,280,282,284,286,288,400 

Flowchart:

Python Code Editor:

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