Python Exercise: Check whether an alphabet is a vowel or consonant

Last update on December 21 2024 07:23:26 (UTC/GMT +8 hours)

Write a Python program to check whether an alphabet is a vowel or consonant.

Pictorial Presentation:

Sample Solution:

Python Code:

# Request input from the user to input a letter of the alphabet and assign it to the variable 'l'
l = input("Input a letter of the alphabet: ")

# Check if the input letter 'l' is present in the tuple containing vowels ('a', 'e', 'i', 'o', 'u')
if l in ('a', 'e', 'i', 'o', 'u'):
    print("%s is a vowel." % l)  # Display a message stating that the input letter is a vowel
# If the input letter is 'y', display a message stating that it sometimes represents a vowel and sometimes a consonant
elif l == 'y':
    print("Sometimes the letter y stands for a vowel, sometimes for a consonant.")
# If the input letter doesn't fall into any of the above conditions, it is considered a consonant; display a message stating so
else:
    print("%s is a consonant." % l) 
	 

Sample Output:

Input a letter of the alphabet: u                                                                             
u is a vowel. 

Flowchart:

Python Code Editor:

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