Python: Matches a word at the end of a string, with optional punctuation
Write a Python program that matches a word at the end of a string, with optional punctuation.
Sample Solution:
Python Code:
import re
def text_match(text):
patterns = '\w+\S*$'
if re.search(patterns, text):
return 'Found a match!'
else:
return('Not matched!')
print(text_match("The quick brown fox jumps over the lazy dog."))
print(text_match("The quick brown fox jumps over the lazy dog. "))
print(text_match("The quick brown fox jumps over the lazy dog "))
Sample Output:
Found a match! Not matched! Not matched!
Pictorial Presentation:
Flowchart:
Python Code Editor:
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