Python: Check if a given set is superset of itself and superset of another given set

Last update on December 21 2024 07:45:40 (UTC/GMT +8 hours)

Write a Python program to check if a given set is a superset of itself and a superset of another given set.

Sample Solution:

Python Code:

# Create a set 'nums' with elements 10, 20, 30, 40, and 50.
nums = {10, 20, 30, 40, 50}

# Print a message to indicate the original set 'nums'.
print("Original set: ", nums)

# Print a message to check if 'nums' is a superset of itself.
print("If nums is superset of itself?")

# Use the 'issuperset()' method to check if 'nums' is a superset of itself and print the result.
print(nums.issuperset(nums)

# Create sets 'num1', 'num2', and 'num3' with different elements.
num1 = {1, 2, 3, 4, 5, 7}
num2 = {2, 4}
num3 = {2, 4}

# Print the contents of sets 'num1', 'num2', and 'num3'.
print("\nnum1 = ", num1)
print("num2 = ", num2)
print("num3 = ", num3)

# Print a message to check if 'num1' is a superset of 'num2'.
print("If num1 is superset of num2:")

# Use the '>' operator to check if 'num1' is a superset of 'num2' and print the result.
print(num1 > num2)

# Print a message to compare 'num2' and 'num3'.
print("Compare num2 and num3:")

# Print a message to check if 'num2' is a superset of 'num3'.
print("If num2 is superset of num3:")

# Use the '>' operator to check if 'num2' is a superset of 'num3' and print the result.
print(num2 > num3)

# Print a message to check if 'num3' is a superset of 'num2'.
print("If num3 is superset of num2:")

# Use the '>' operator to check if 'num3' is a superset of 'num2' and print the result.
print(num3 > num2) 

Sample Output:

Original set:  {40, 10, 50, 20, 30}
If nums is superset of itself?
True

num1 =  {1, 2, 3, 4, 5, 7}
num2 =  {2, 4}
num3 =  {2, 4}
If mum1 is superset of num2:
True
Compare mum2 and num3:
If mum2 is superset of num3:
False
If mum3 is superset of num2:
False

Python Code Editor:

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