Python: Remove an item from a set if it is present in the set

Last update on December 21 2024 07:45:48 (UTC/GMT +8 hours)

Write a Python program to remove an item from a set if it is present in the set.

Visual Presentation:

Sample Solution:

Python Code:

# Create a new set 'num_set' with the elements 0, 1, 2, 3, 4, and 5 using a list:
num_set = set([0, 1, 2, 3, 4, 5])

# Print a message to indicate the original set elements:
print("Original set elements:")

# Print the contents of the 'num_set':
print(num_set)

# Print a message to indicate the removal of 0 from the set:
print("\nRemove 0 from the said set:")

# Remove the element 4 from the 'num_set' using the 'discard' method:
num_set.discard(4)

# Print the updated 'num_set' after removing 4:
print(num_set)

# Print a message to indicate the removal of 5 from the set:
print("\nRemove 5 from the said set:")

# Remove the element 5 from the 'num_set' using the 'discard' method:
num_set.discard(5)

# Print the updated 'num_set' after removing 5:
print(num_set)

# Print a message to indicate the removal of 2 from the set:
print("\nRemove 2 from the said set:")

# Remove the element 5 from the 'num_set' using the 'discard' method (note: this should remove 2, not 5):
num_set.discard(5)

# Print the updated 'num_set' after removing 5 (actually removing 2):
print(num_set)

# Print a message to indicate the removal of 7 from the set:
print("\nRemove 7 from the said set:")

# Remove the element 15 from the 'num_set' using the 'discard' method (note: this should not affect the set as 15 is not in it):
num_set.discard(15)

# Print the 'num_set' without any changes, as 15 was not present in the set:
print(num_set)  

Sample Output:

Original set elements:
{0, 1, 2, 3, 4, 5}

Remove 0 from the said set:
{0, 1, 2, 3, 5}

Remove 5 from the said set:
{0, 1, 2, 3}

Remove 2 from the said set:
{0, 1, 2, 3}

Remove 7 from the said set:
{0, 1, 2, 3}

Python Code Editor:

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