Python: Create a symmetric difference

Last update on December 21 2024 07:45:49 (UTC/GMT +8 hours)

Write a Python program to create a symmetric difference.

From Wikipedia,
In mathematics, the symmetric difference, also known as the disjunctive union, of two sets is the set of elements which are in either of the sets and not in their intersection. The symmetric difference of the sets A and B is commonly denoted by

For example, the symmetric difference of the sets {1,2,3} and {3,4} is {1,2,4}.

Sample Solution-1:

Using symmetric_difference() Method

Python Code:

# Create a set 'setc1' with elements "green" and "blue":
setc1 = set(["green", "blue"])

# Create a set 'setc2' with elements "blue" and "yellow":
setc2 = set(["blue", "yellow"])

# Print a message to indicate the original sets:
print("Original sets:")

# Print the contents of 'setc1' and 'setc2':
print(setc1)
print(setc2)

# Calculate the symmetric difference of 'setc1' and 'setc2' and store it in 'r1':
r1 = setc1.symmetric_difference(setc2)

# Print a message to indicate the symmetric difference of 'setc1 - setc2':
print("\nSymmetric difference of setc1 - setc2:")

# Print the result 'r1', which contains elements that are unique to each of 'setc1' and 'setc2':
print(r1)

# Calculate the symmetric difference of 'setc2' and 'setc1' and store it in 'r2':
r2 = setc2.symmetric_difference(setc1)

# Print a message to indicate the symmetric difference of 'setc2 - setc1':
print("\nSymmetric difference of setc2 - setc1:")

# Print the result 'r2', which is the same as 'r1' and contains elements unique to each set:
print(r2)

# Create a set 'setn1' with repeated elements, including 1, 2, 3, 4, and 5:
setn1 = set([1, 1, 2, 3, 4, 5])

# Create a set 'setn2' with elements including 1, 5, 6, 7, 8, and 9:
setn2 = set([1, 5, 6, 7, 8, 9])

# Print a message to indicate the original sets:
print("\nOriginal sets:")

# Print the contents of 'setn1' and 'setn2':
print(setn1)
print(setn2)

# Calculate the symmetric difference of 'setn1' and 'setn2' and store it in 'r1':
r1 = setn1.symmetric_difference(setn2)

# Print a message to indicate the symmetric difference of 'setn1 - setn2':
print("\nSymmetric difference of setn1 - setn2:")

# Print the result 'r1', which contains elements unique to each of 'setn1' and 'setn2':
print(r1)

# Calculate the symmetric difference of 'setn2' and 'setn1' and store it in 'r2':
r2 = setn2.symmetric_difference(setn1)

# Print a message to indicate the symmetric difference of 'setn2 - setn1':
print("\nSymmetric difference of setn2 - setn1:")

# Print the result 'r2', which is the same as 'r1' and contains elements unique to each set:
print(r2) 

Sample Output:

Original sets:
{'blue', 'green'}
{'blue', 'yellow'}

Symmetric difference of setc1 - setc2:
{'yellow', 'green'}

Symmetric difference of setc2 - setc1:
{'yellow', 'green'}

Original sets:
{1, 2, 3, 4, 5}
{1, 5, 6, 7, 8, 9}

Symmetric difference of setn1 - setn2:
{2, 3, 4, 6, 7, 8, 9}

Symmetric difference of setn2 - setn1:
{2, 3, 4, 6, 7, 8, 9}

Visual Presentation:

Sample Solution-2:

Using symmetric difference operator(^)

Python Code:

# Create a set 'setc1' with elements "green" and "blue":
setc1 = set(["green", "blue"])

# Create a set 'setc2' with elements "blue" and "yellow":
setc2 = set(["blue", "yellow"])

# Print a message to indicate the original sets:
print("Original sets:")

# Print the contents of 'setc1' and 'setc2':
print(setc1)
print(setc2)

# Calculate the symmetric difference of 'setc1' and 'setc2' using the '^' operator and store it in 'r1':
r1 = setc1 ^ setc2

# Print a message to indicate the symmetric difference of 'setc1 - setc2':
print("\nSymmetric difference of setc1 - setc2:")

# Print the result 'r1', which contains elements that are unique to each of 'setc1' and 'setc2':
print(r1)

# Calculate the symmetric difference of 'setc2' and 'setc1' using the '^' operator and store it in 'r2':
r2 = setc2 ^ setc1

# Print a message to indicate the symmetric difference of 'setc2 - setc1':
print("\nSymmetric difference of setc2 - setc1:")

# Print the result 'r2', which is the same as 'r1' and contains elements unique to each set:
print(r2)

# Create a set 'setn1' with repeated elements, including 1, 2, 3, 4, and 5:
setn1 = set([1, 1, 2, 3, 4, 5])

# Create a set 'setn2' with elements including 1, 5, 6, 7, 8, and 9:
setn2 = set([1, 5, 6, 7, 8, 9])

# Print a message to indicate the original sets:
print("\nOriginal sets:")

# Print the contents of 'setn1' and 'setn2':
print(setn1)
print(setn2)

# Calculate the symmetric difference of 'setn1' and 'setn2' using the '^' operator and store it in 'r1':
r1 = setn1 ^ setn2

# Print a message to indicate the symmetric difference of 'setn1 - setn2':
print("\nSymmetric difference of setn1 - setn2:")

# Print the result 'r1', which contains elements unique to each of 'setn1' and 'setn2':
print(r1)

# Calculate the symmetric difference of 'setn2' and 'setn1' using the '^' operator and store it in 'r2':
r2 = setn2 ^ setn1

# Print a message to indicate the symmetric difference of 'setn2 - setn1':
print("\nSymmetric difference of setn2 - setn1:")

# Print the result 'r2', which is the same as 'r1' and contains elements unique to each set:
print(r2) 

Sample Output:

Original sets:
{'blue', 'green'}
{'yellow', 'blue'}

Symmetric difference of setc1 - setc2:
{'yellow', 'green'}

Symmetric difference of setc2 - setc1:
{'yellow', 'green'}

Original sets:
{1, 2, 3, 4, 5}
{1, 5, 6, 7, 8, 9}

Symmetric difference of setn1 - setn2:
{2, 3, 4, 6, 7, 8, 9}

Symmetric difference of setn2 - setn1:
{2, 3, 4, 6, 7, 8, 9}

Visual Presentation:

Python Code Editor:

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