Python: Delete a specific row from a given SQLite table
Write a Python program to delete a specific row from a given SQLite table.
Sample Solution:
Python Code :
import sqlite3
from sqlite3 import Error
def sql_connection():
try:
conn = sqlite3.connect('mydatabase.db')
return conn
except Error:
print(Error)
def sql_table(conn):
cursorObj = conn.cursor()
# Create the table
cursorObj.execute("CREATE TABLE salesman(salesman_id n(5), name char(30), city char(35), commission decimal(7,2));")
# Insert records
cursorObj.executescript("""
INSERT INTO salesman VALUES(5001,'James Hoog', 'New York', 0.15);
INSERT INTO salesman VALUES(5002,'Nail Knite', 'Paris', 0.25);
INSERT INTO salesman VALUES(5003,'Pit Alex', 'London', 0.15);
INSERT INTO salesman VALUES(5004,'Mc Lyon', 'Paris', 0.35);
INSERT INTO salesman VALUES(5005,'Paul Adam', 'Rome', 0.45);
""")
cursorObj.execute("SELECT * FROM salesman")
rows = cursorObj.fetchall()
print("Agent details:")
for row in rows:
print(row)
print("\nDelete Salesman of ID 5003:")
s_id = 5003
cursorObj.execute("""
DELETE FROM salesman
WHERE salesman_id = ?
""", (s_id,))
conn.commit()
cursorObj.execute("SELECT * FROM salesman")
rows = cursorObj.fetchall()
print("\nAfter updating Agent details:")
for row in rows:
print(row)
sqllite_conn = sql_connection()
sql_table(sqllite_conn)
if (sqllite_conn):
sqllite_conn.close()
print("\nThe SQLite connection is closed.")
Sample Output:
Agent details: (5001, 'James Hoog', 'New York', 0.15) (5002, 'Nail Knite', 'Paris', 0.25) (5003, 'Pit Alex', 'London', 0.15) (5004, 'Mc Lyon', 'Paris', 0.35) (5005, 'Paul Adam', 'Rome', 0.45) Delete Salesman of ID 5003: After updating Agent details: (5001, 'James Hoog', 'New York', 0.15) (5002, 'Nail Knite', 'Paris', 0.25) (5004, 'Mc Lyon', 'Paris', 0.35) (5005, 'Paul Adam', 'Rome', 0.45) The SQLite connection is closed.
Python Code Editor:
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