Python: Count characters at same position in a given string as in English alphabet

Last update on December 21 2024 07:46:59 (UTC/GMT +8 hours)

Count chars matching English alphabet position.

Write a Python program to count characters at the same position in a given string (lower and uppercase characters) as in the English alphabet.

Visual Presentation:

Sample Solution:

Python Code:

# Function to count characters at same position
def count_char_position(str1):

  count_chars = 0

  # Iterate through string
  for i in range(len(str1)):

    # Check if position matches ASCII value
    if ((i == ord(str1[i]) - ord('A')) or 
        (i == ord(str1[i]) - ord('a'))):
      
      count_chars += 1

  return count_chars

# Get input string  
str1 = input("Input a string: ")

# Print result
print("Number of characters of the said string at same position as in English alphabet:")
print(count_char_position(str1)) 

Sample Output:

Input a string:  xbcefg
Number of characters of the said string at same position as in English alphabet:
2

Flowchart:

Python Code Editor:

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