Python Tkinter: Building a color picker dialog

Last update on April 25 2025 12:53:20 (UTC/GMT +8 hours)

Write a Python program to build a color picker dialog that lets the user choose a color and displays it using Tkinter.

Sample Solution:

Python Code:

import tkinter as tk
from tkinter import colorchooser

def open_color_picker():
    color = colorchooser.askcolor(title="Pick a Color")
    if color[1]:  # Check if a color was chosen (not canceled)
        selected_color_label.config(text=f"Selected Color: {color[0]}")
        selected_color_label.config(bg=color[1])

root = tk.Tk()
root.title("Color Picker Example")

pick_color_button = tk.Button(root, text="Pick a Color", command=open_color_picker)
pick_color_button.pack(padx=20, pady=20)

selected_color_label = tk.Label(root, text="Selected Color:", padx=20, pady=10)
selected_color_label.pack()

root.mainloop()

Explanation:

In the exercise above -

Import tkinter as tk and filedialog for creating the GUI components and opening the color picker dialog.
Define the "open_color_picker()" function, which opens the color picker dialog using colorchooser.askcolor(). If a color is chosen (not canceled), it updates a label with the selected color and sets the label's background color to the chosen color.
Create the main Tkinter window, set its title, and create a button labeled "Pick a Color" that calls the "open_color_picker()" function when clicked.
Create a label to display the selected color with color RGB code and background color.
The main event loop, root.mainloop(), starts the Tkinter application.

Sample Output:

Flowchart:

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