Python Tkinter Color Picker Example

Last update on December 21 2024 07:47:54 (UTC/GMT +8 hours)

Write a Python program that designs a color picker application using Tkinter. When a color is selected from a color dialog, change the foreground color of a Label widget.

Sample Solution:

Python Code:

import tkinter as tk
from tkinter import colorchooser

def pick_color():
    color = colorchooser.askcolor()[1]  # Ask the user to choose a color and get the hex code
    if color:
        color_label.config(foreground=color)  # Set the foreground color of the Label

# Create the main window
root = tk.Tk()
root.title("Color Picker")

# Create a Label widget
color_label = tk.Label(root, text="Change the foreground color", font=("Helvetica", 18))
color_label.pack(pady=20)

# Create a button to open the color dialog
color_button = tk.Button(root, text="Pick a Color", command=pick_color)
color_button.pack()

# Start the Tkinter main loop
root.mainloop()

Explanation:

In the exercise above -

• Import the necessary modules: "tkinter" and "tkinter.colorchooser".
• Define a "pick_color()" function that opens a color dialog using "colorchooser.askcolor()". This function returns a tuple where the second element is the selected color in hexadecimal format.
• If the user selects a color (i.e., if color is not None), use the config method to change the foreground color of the "color_label" Label widget to the selected color.
• Create the main window and set its title.
• Create a 'Label' widget (color_label) and a button (color_button) to initiate the color selection process.
• When the button is clicked, the "pick_color()" function is called, allowing the user to choose a color.
• The chosen color is applied as the foreground color to the 'Label' widget.
• Finally, start the Tkinter main loop with "root.mainloop()".

Output:

Flowchart:

Python Code Editor:

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